Question
Solve the inequality
Solve the inequality by testing the values in the interval
Solve the inequality by separating into cases
0<x<2
Alternative Form
x∈(0,2)
Evaluate
(3x×10)(2x2×1)(2−x)>0
Remove the parentheses
3x×10×2x2×1×(2−x)>0
Multiply the terms
More Steps

Evaluate
3x×10×2x2×1×(2−x)
Rewrite the expression
3x×10×2x2(2−x)
Multiply the terms
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Evaluate
3×10×2
Multiply the terms
30×2
Multiply the numbers
60
60x×x2(2−x)
Multiply the terms with the same base by adding their exponents
60x1+2(2−x)
Add the numbers
60x3(2−x)
60x3(2−x)>0
Rewrite the expression
60x3(2−x)=0
Elimination the left coefficient
x3(2−x)=0
Separate the equation into 2 possible cases
x3=02−x=0
The only way a power can be 0 is when the base equals 0
x=02−x=0
Solve the equation
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Evaluate
2−x=0
Move the constant to the right-hand side and change its sign
−x=0−2
Removing 0 doesn't change the value,so remove it from the expression
−x=−2
Change the signs on both sides of the equation
x=2
x=0x=2
Determine the test intervals using the critical values
x<00<x<2x>2
Choose a value form each interval
x1=−1x2=1x3=3
To determine if x<0 is the solution to the inequality,test if the chosen value x=−1 satisfies the initial inequality
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Evaluate
60(−1)3(2−(−1))>0
Simplify
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Evaluate
60(−1)3(2−(−1))
Subtract the terms
60(−1)3×3
Multiply the terms
180(−1)3
Evaluate the power
180(−1)
Multiply the numbers
−180
−180>0
Check the inequality
false
x<0 is not a solutionx2=1x3=3
To determine if 0<x<2 is the solution to the inequality,test if the chosen value x=1 satisfies the initial inequality
More Steps

Evaluate
60×13×(2−1)>0
Simplify
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Evaluate
60×13×(2−1)
Subtract the numbers
60×13×1
1 raised to any power equals to 1
60×1×1
Multiply the terms
60
60>0
Check the inequality
true
x<0 is not a solution0<x<2 is the solutionx3=3
To determine if x>2 is the solution to the inequality,test if the chosen value x=3 satisfies the initial inequality
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Evaluate
60×33(2−3)>0
Simplify
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Evaluate
60×33(2−3)
Subtract the numbers
60×33(−1)
Any expression multiplied by 1 remains the same
−60×33
Multiply the terms
−1620
−1620>0
Check the inequality
false
x<0 is not a solution0<x<2 is the solutionx>2 is not a solution
Solution
0<x<2
Alternative Form
x∈(0,2)
Show Solution
