Solve (3y-1)^6 = 80

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Type your math problem... (3y-1)^6 = 80

Question

Solve the equation

y_{1} = \frac{- 6 80 + 1}{3}, y_{2} = \frac{6 80 + 1}{3}

Alternative Form

y_{1} \approx - 0.358594, y_{2} \approx 1.025261

Evaluate

(3 y - 1)^{6} = 80

Take the root of both sides of the equation and remember to use both positive and negative roots

3 y - 1 = \pm 680

Separate the equation into 2 possible cases

3 y - 1 = 680 3 y - 1 = - 680

Calculate

More Steps

Evaluate

3 y - 1 = 680

Move the constant to the right-hand side and change its sign

3 y = 680 + 1

Divide both sides

\frac{3 y}{3} = \frac{6 80 + 1}{3}

Divide the numbers

y = \frac{6 80 + 1}{3}

y = \frac{6 80 + 1}{3} 3 y - 1 = - 680

Calculate

More Steps

Evaluate

3 y - 1 = - 680

Move the constant to the right-hand side and change its sign

3 y = - 680 + 1

Divide both sides

\frac{3 y}{3} = \frac{- 6 80 + 1}{3}

Divide the numbers

y = \frac{- 6 80 + 1}{3}

y = \frac{6 80 + 1}{3} y = \frac{- 6 80 + 1}{3}

Solution

y_{1} = \frac{- 6 80 + 1}{3}, y_{2} = \frac{6 80 + 1}{3}

Alternative Form

y_{1} \approx - 0.358594, y_{2} \approx 1.025261

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