Algebra
Calculus
Trigonometry
Matrix
Question
Simplify the expression
216g3j21
Evaluate
12g3×18j25j−1÷(5j−1)
Multiply the terms
216g3j25j−1÷(5j−1)
Multiply by the reciprocal
216g3j25j−1×5j−11
Cancel out the common factor 5j−1
216g3j21×1
Solution
216g3j21
Show Solution
Find the excluded values
g=0,j=0,j=51
Evaluate
12g3×18j25j−1÷(5j−1)
To find the excluded values,set the denominators equal to 0
g3j2=05j−1=0
Solve the equations
More Steps
Evaluate
g3j2=0
Separate the equation into 2 possible cases
g3=0j2=0
The only way a power can be 0 is when the base equals 0
g=0j2=0
The only way a power can be 0 is when the base equals 0
g=0j=0
g=0j=05j−1=0
Solve the equations
More Steps
Evaluate
5j−1=0
Move the constant to the right-hand side and change its sign
5j=0+1
Removing 0 doesn't change the value,so remove it from the expression
5j=1
Divide both sides
55j=51
Divide the numbers
j=51
g=0j=0j=51
Solution
g=0,j=0,j=51
Show Solution