Question
Solve the inequality
Solve the inequality by testing the values in the interval
Solve the inequality by separating into cases
0<x<65
Alternative Form
x∈(0,65)
Evaluate
4x×16x−5<0
Find the domain
More Steps

Evaluate
4x×1=0
Multiply the terms
4x=0
Rewrite the expression
x=0
4x×16x−5<0,x=0
Multiply the terms
4x6x−5<0
Set the numerator and denominator of 4x6x−5 equal to 0 to find the values of x where sign changes may occur
6x−5=04x=0
Calculate
More Steps

Evaluate
6x−5=0
Move the constant to the right-hand side and change its sign
6x=0+5
Removing 0 doesn't change the value,so remove it from the expression
6x=5
Divide both sides
66x=65
Divide the numbers
x=65
x=654x=0
Calculate
x=65x=0
Determine the test intervals using the critical values
x<00<x<65x>65
Choose a value form each interval
x1=−1x2=125x3=2
To determine if x<0 is the solution to the inequality,test if the chosen value x=−1 satisfies the initial inequality
More Steps

Evaluate
4(−1)6(−1)−5<0
Simplify
More Steps

Evaluate
4(−1)6(−1)−5
Simplify
4(−1)−6−5
Simplify
−4−6−5
Subtract the numbers
−4−11
Cancel out the common factor −1
411
411<0
Calculate
2.75<0
Check the inequality
false
x<0 is not a solutionx2=125x3=2
To determine if 0<x<65 is the solution to the inequality,test if the chosen value x=125 satisfies the initial inequality
More Steps

Evaluate
4×1256×125−5<0
Simplify
More Steps

Evaluate
4×1256×125−5
Multiply the numbers
4×12525−5
Multiply the numbers
3525−5
Subtract the numbers
35−25
Multiply by the reciprocal
−25×53
Reduce the numbers
−21×3
Multiply the numbers
−23
−23<0
Calculate
−1.5<0
Check the inequality
true
x<0 is not a solution0<x<65 is the solutionx3=2
To determine if x>65 is the solution to the inequality,test if the chosen value x=2 satisfies the initial inequality
More Steps

Evaluate
4×26×2−5<0
Simplify
More Steps

Evaluate
4×26×2−5
Multiply the numbers
4×212−5
Multiply the numbers
812−5
Subtract the numbers
87
87<0
Calculate
0.875<0
Check the inequality
false
x<0 is not a solution0<x<65 is the solutionx>65 is not a solution
The original inequality is a strict inequality,so does not include the critical value ,the final solution is 0<x<65
0<x<65
Check if the solution is in the defined range
0<x<65,x=0
Solution
0<x<65
Alternative Form
x∈(0,65)
Show Solution
