Solve (7x^2)(2x^3 5)(x^2-4x-9)

Question

Simplify the expression

70 x^{7} - 280 x^{6} - 630 x^{5}

Show Solution

x_{1} = 2 - 13, x_{2} = 0, x_{3} = 2 + 13

Alternative Form

x_{1} \approx - 1.605551, x_{2} = 0, x_{3} \approx 5.605551

Evaluate

(7 x^{2}) (2 x^{3} \times 5) (x^{2} - 4 x - 9)

To find the roots of the expression,set the expression equal to 0

(7 x^{2}) (2 x^{3} \times 5) (x^{2} - 4 x - 9) = 0

Multiply the terms

7 x^{2} (2 x^{3} \times 5) (x^{2} - 4 x - 9) = 0

Multiply the terms

7 x^{2} \times 10 x^{3} (x^{2} - 4 x - 9) = 0

Multiply

More Steps

70 x^{5} (x^{2} - 4 x - 9) = 0

Elimination the left coefficient

x^{5} (x^{2} - 4 x - 9) = 0

Separate the equation into 2 possible cases

x^{5} = 0 x^{2} - 4 x - 9 = 0

The only way a power can be 0 is when the base equals 0

x = 0 x^{2} - 4 x - 9 = 0

Solve the equation

More Steps

x = 0 x = 2 + 13 x = 2 - 13

Solution

x_{1} = 2 - 13, x_{2} = 0, x_{3} = 2 + 13

Alternative Form

x_{1} \approx - 1.605551, x_{2} = 0, x_{3} \approx 5.605551

Show Solution