Solve (8p-2)(6p+2)

Question

Simplify the expression

48 p^{2} + 4 p - 4

Evaluate

(8 p - 2) (6 p + 2)

Apply the distributive property

8 p \times 6 p + 8 p \times 2 - 2 \times 6 p - 2 \times 2

Multiply the terms

More Steps

Evaluate

8 p \times 6 p

Multiply the numbers

48 p \times p

Multiply the terms

48 p^{2}

48 p^{2} + 8 p \times 2 - 2 \times 6 p - 2 \times 2

Multiply the numbers

48 p^{2} + 16 p - 2 \times 6 p - 2 \times 2

Multiply the numbers

48 p^{2} + 16 p - 12 p - 2 \times 2

Multiply the numbers

48 p^{2} + 16 p - 12 p - 4

Solution

More Steps

Evaluate

16 p - 12 p

Collect like terms by calculating the sum or difference of their coefficients

(16 - 12) p

Subtract the numbers

4 p

48 p^{2} + 4 p - 4

Show Solution

4 (4 p - 1) (3 p + 1)

Evaluate

(8 p - 2) (6 p + 2)

Factor the expression

2 (4 p - 1) (6 p + 2)

Factor the expression

2 (4 p - 1) \times 2 (3 p + 1)

Solution

4 (4 p - 1) (3 p + 1)

Show Solution

p_{1} = - \frac{1}{3}, p_{2} = \frac{1}{4}

Alternative Form

p_{1} = - 0. \dot{3}, p_{2} = 0.25

Evaluate

(8 p - 2) (6 p + 2)

To find the roots of the expression,set the expression equal to 0

(8 p - 2) (6 p + 2) = 0

Separate the equation into 2 possible cases

8 p - 2 = 0 6 p + 2 = 0

Solve the equation

More Steps

Evaluate

8 p - 2 = 0

Move the constant to the right-hand side and change its sign

8 p = 0 + 2

Removing 0 doesn't change the value,so remove it from the expression

8 p = 2

Divide both sides

\frac{8 p}{8} = \frac{2}{8}

Divide the numbers

p = \frac{2}{8}

Cancel out the common factor 2

p = \frac{1}{4}

p = \frac{1}{4} 6 p + 2 = 0

Solve the equation

More Steps

Evaluate

6 p + 2 = 0

Move the constant to the right-hand side and change its sign

6 p = 0 - 2

Removing 0 doesn't change the value,so remove it from the expression

6 p = - 2

Divide both sides

\frac{6 p}{6} = \frac{- 2}{6}

Divide the numbers

p = \frac{- 2}{6}

Divide the numbers

More Steps

Evaluate

\frac{- 2}{6}

Cancel out the common factor 2

\frac{- 1}{3}

Use \frac{- a}{b} = \frac{a}{- b} = - \frac{a}{b} to rewrite the fraction

- \frac{1}{3}

p = - \frac{1}{3}

p = \frac{1}{4} p = - \frac{1}{3}

Solution

p_{1} = - \frac{1}{3}, p_{2} = \frac{1}{4}

Alternative Form

p_{1} = - 0. \dot{3}, p_{2} = 0.25

Show Solution