Algebra
Calculus
Trigonometry
Matrix
Question
Simplify the expression
27c3−81c2+81c−27
Evaluate
(c−1)3×27
Use the commutative property to reorder the terms
27(c−1)3
Expand the expression
More Steps
Evaluate
(c−1)3
Use (a−b)3=a3−3a2b+3ab2−b3 to expand the expression
c3−3c2×1+3c×12−13
Calculate
c3−3c2+3c−1
27(c3−3c2+3c−1)
Apply the distributive property
27c3−27×3c2+27×3c−27×1
Multiply the numbers
27c3−81c2+27×3c−27×1
Multiply the numbers
27c3−81c2+81c−27×1
Solution
27c3−81c2+81c−27
Show Solution
Find the roots
c=1
Evaluate
(c−1)3×27
To find the roots of the expression,set the expression equal to 0
(c−1)3×27=0
Use the commutative property to reorder the terms
27(c−1)3=0
Rewrite the expression
(c−1)3=0
The only way a power can be 0 is when the base equals 0
c−1=0
Move the constant to the right-hand side and change its sign
c=0+1
Solution
c=1
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