Question
Simplify the expression
h5−h4−h3
Evaluate
(h2×h×1)(h2−h−1)
Remove the parentheses
h2×h×1×(h2−h−1)
Rewrite the expression
h2×h(h2−h−1)
Multiply the terms with the same base by adding their exponents
h2+1(h2−h−1)
Add the numbers
h3(h2−h−1)
Apply the distributive property
h3×h2−h3×h−h3×1
Multiply the terms
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Evaluate
h3×h2
Use the product rule an×am=an+m to simplify the expression
h3+2
Add the numbers
h5
h5−h3×h−h3×1
Multiply the terms
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Evaluate
h3×h
Use the product rule an×am=an+m to simplify the expression
h3+1
Add the numbers
h4
h5−h4−h3×1
Solution
h5−h4−h3
Show Solution

Find the roots
h1=21−5,h2=0,h3=21+5
Alternative Form
h1≈−0.618034,h2=0,h3≈1.618034
Evaluate
(h2×h×1)(h2−h−1)
To find the roots of the expression,set the expression equal to 0
(h2×h×1)(h2−h−1)=0
Multiply the terms
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Multiply the terms
h2×h×1
Rewrite the expression
h2×h
Use the product rule an×am=an+m to simplify the expression
h2+1
Add the numbers
h3
h3(h2−h−1)=0
Separate the equation into 2 possible cases
h3=0h2−h−1=0
The only way a power can be 0 is when the base equals 0
h=0h2−h−1=0
Solve the equation
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Evaluate
h2−h−1=0
Substitute a=1,b=−1 and c=−1 into the quadratic formula h=2a−b±b2−4ac
h=21±(−1)2−4(−1)
Simplify the expression
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Evaluate
(−1)2−4(−1)
Evaluate the power
1−4(−1)
Simplify
1−(−4)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
1+4
Add the numbers
5
h=21±5
Separate the equation into 2 possible cases
h=21+5h=21−5
h=0h=21+5h=21−5
Solution
h1=21−5,h2=0,h3=21+5
Alternative Form
h1≈−0.618034,h2=0,h3≈1.618034
Show Solution
