Question
Simplify the expression
4j2−5j+1
Evaluate
(j−1)(4j−1)
Apply the distributive property
j×4j−j×1−4j−(−1)
Multiply the terms
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Evaluate
j×4j
Use the commutative property to reorder the terms
4j×j
Multiply the terms
4j2
4j2−j×1−4j−(−1)
Any expression multiplied by 1 remains the same
4j2−j−4j−(−1)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
4j2−j−4j+1
Solution
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Evaluate
−j−4j
Collect like terms by calculating the sum or difference of their coefficients
(−1−4)j
Subtract the numbers
−5j
4j2−5j+1
Show Solution

Find the roots
j1=41,j2=1
Alternative Form
j1=0.25,j2=1
Evaluate
(j−1)(4j−1)
To find the roots of the expression,set the expression equal to 0
(j−1)(4j−1)=0
Separate the equation into 2 possible cases
j−1=04j−1=0
Solve the equation
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Evaluate
j−1=0
Move the constant to the right-hand side and change its sign
j=0+1
Removing 0 doesn't change the value,so remove it from the expression
j=1
j=14j−1=0
Solve the equation
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Evaluate
4j−1=0
Move the constant to the right-hand side and change its sign
4j=0+1
Removing 0 doesn't change the value,so remove it from the expression
4j=1
Divide both sides
44j=41
Divide the numbers
j=41
j=1j=41
Solution
j1=41,j2=1
Alternative Form
j1=0.25,j2=1
Show Solution
