Question
Simplify the expression
2v3−v2
Evaluate
v2(2v−1)
Apply the distributive property
v2×2v−v2×1
Multiply the terms
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Evaluate
v2×2v
Use the commutative property to reorder the terms
2v2×v
Multiply the terms
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Evaluate
v2×v
Use the product rule an×am=an+m to simplify the expression
v2+1
Add the numbers
v3
2v3
2v3−v2×1
Solution
2v3−v2
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Find the roots
v1=0,v2=21
Alternative Form
v1=0,v2=0.5
Evaluate
(v2)(2v−1)
To find the roots of the expression,set the expression equal to 0
(v2)(2v−1)=0
Calculate
v2(2v−1)=0
Separate the equation into 2 possible cases
v2=02v−1=0
The only way a power can be 0 is when the base equals 0
v=02v−1=0
Solve the equation
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Evaluate
2v−1=0
Move the constant to the right-hand side and change its sign
2v=0+1
Removing 0 doesn't change the value,so remove it from the expression
2v=1
Divide both sides
22v=21
Divide the numbers
v=21
v=0v=21
Solution
v1=0,v2=21
Alternative Form
v1=0,v2=0.5
Show Solution
