Question
Simplify the expression
2x3+6x
Evaluate
(x+1)3+(x−1)3
Expand the expression
x3+3x2+3x+1+(x−1)3
Expand the expression
x3+3x2+3x+1+x3−3x2+3x−1
Add the terms
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Evaluate
x3+x3
Collect like terms by calculating the sum or difference of their coefficients
(1+1)x3
Add the numbers
2x3
2x3+3x2+3x+1−3x2+3x−1
The sum of two opposites equals 0
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Evaluate
3x2−3x2
Collect like terms
(3−3)x2
Add the coefficients
0×x2
Calculate
0
2x3+0+3x+1+3x−1
Remove 0
2x3+3x+1+3x−1
Add the terms
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Evaluate
3x+3x
Collect like terms by calculating the sum or difference of their coefficients
(3+3)x
Add the numbers
6x
2x3+6x+1−1
Solution
2x3+6x
Show Solution

Factor the expression
2x(x2+3)
Evaluate
(x+1)3+(x−1)3
Use a3+b3=(a+b)(a2−ab+b2) to factor the expression
(x+1+x−1)((x+1)2−(x+1)(x−1)+(x−1)2)
Evaluate
(x+1+x−1)((x+1)2+(−x−1)(x−1)+(x−1)2)
Calculate
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Simplify
x+1+x−1
Add the terms
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Evaluate
x+x
Collect like terms by calculating the sum or difference of their coefficients
(1+1)x
Add the numbers
2x
2x+1−1
Since two opposites add up to 0,remove them form the expression
2x
2x((x+1)2+(−x−1)(x−1)+(x−1)2)
Solution
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Simplify
(x+1)2+(−x−1)(x−1)+(x−1)2
Simplify
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Simplify
(−x−1)(x−1)
Apply the distributive property
−x×x−x(−1)−x−(−1)
Multiply the terms
−x2−x(−1)−x−(−1)
Multiplying or dividing an even number of negative terms equals a positive
−x2+x−x−(−1)
When there is - in front of an expression in parentheses change the sign of each term of the expression and remove the parentheses
−x2+x−x+1
(x+1)2−x2+x−x+1+(x−1)2
The sum of two opposites equals 0
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Evaluate
x−x
Collect like terms
(1−1)x
Add the coefficients
0×x
Calculate
0
(x+1)2−x2+0+1+(x−1)2
Remove 0
(x+1)2−x2+1+(x−1)2
Expand the expression
x2+2x+1−x2+1+(x−1)2
Expand the expression
x2+2x+1−x2+1+x2−2x+1
Calculate the sum or difference
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Evaluate
x2−x2+x2
Collect like terms by calculating the sum or difference of their coefficients
(1−1+1)x2
Calculate the sum or difference
x2
x2+2x+1+1−2x+1
The sum of two opposites equals 0
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Evaluate
2x−2x
Collect like terms
(2−2)x
Add the coefficients
0×x
Calculate
0
x2+0+1+1+1
Remove 0
x2+1+1+1
Add the numbers
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Evaluate
1+1+1
Add the numbers
2+1
Add the numbers
3
x2+3
2x(x2+3)
Show Solution

Find the roots
x1=−3×i,x2=3×i,x3=0
Alternative Form
x1≈−1.732051i,x2≈1.732051i,x3=0
Evaluate
(x+1)3+(x−1)3
To find the roots of the expression,set the expression equal to 0
(x+1)3+(x−1)3=0
Factor the expression
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Evaluate
(x+1)3+(x−1)3
Use a3+b3=(a+b)(a2−ab+b2) to factor the expression
(x+1+x−1)((x+1)2−(x+1)(x−1)+(x−1)2)
Evaluate
(x+1+x−1)((x+1)2+(−x−1)(x−1)+(x−1)2)
(x+1+x−1)((x+1)2+(−x−1)(x−1)+(x−1)2)=0
Separate the equation into 2 possible cases
x+1+x−1=0(x+1)2+(−x−1)(x−1)+(x−1)2=0
Solve the equation
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Evaluate
x+1+x−1=0
Calculate the sum or difference
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Evaluate
x+1+x−1
Add the terms
2x+1−1
Since two opposites add up to 0,remove them form the expression
2x
2x=0
Rewrite the expression
x=0
x=0(x+1)2+(−x−1)(x−1)+(x−1)2=0
Solve the equation
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Evaluate
(x+1)2+(−x−1)(x−1)+(x−1)2=0
Calculate
More Steps

Evaluate
(x+1)2+(−x−1)(x−1)+(x−1)2
Expand the expression
x2+2x+1+(−x−1)(x−1)+(x−1)2
Expand the expression
x2+2x+1+1−x2+(x−1)2
Expand the expression
x2+2x+1+1−x2+x2−2x+1
Calculate the sum or difference
x2+2x+1+1−2x+1
The sum of two opposites equals 0
x2+0+1+1+1
Remove 0
x2+1+1+1
Add the numbers
x2+3
x2+3=0
Move the constant to the right-hand side and change its sign
x2=0−3
Removing 0 doesn't change the value,so remove it from the expression
x2=−3
Take the root of both sides of the equation and remember to use both positive and negative roots
x=±−3
Simplify the expression
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Evaluate
−3
Evaluate the power
3×−1
Evaluate the power
3×i
x=±(3×i)
Separate the equation into 2 possible cases
x=3×ix=−3×i
x=0x=3×ix=−3×i
Solution
x1=−3×i,x2=3×i,x3=0
Alternative Form
x1≈−1.732051i,x2≈1.732051i,x3=0
Show Solution
