Solve (x 1)^(3)-5x 7=0

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Type your math problem... (x 1)^(3)-5x 7=0

Question

Solve the equation

x_{1} = - 35, x_{2} = 0, x_{3} = 35

Alternative Form

x_{1} \approx - 5.91608, x_{2} = 0, x_{3} \approx 5.91608

Evaluate

(x \times 1)^{3} - 5 x \times 7 = 0

Simplify

More Steps

Evaluate

(x \times 1)^{3} - 5 x \times 7

Any expression multiplied by 1 remains the same

x^{3} - 5 x \times 7

Multiply the terms

x^{3} - 35 x

x^{3} - 35 x = 0

Factor the expression

x (x^{2} - 35) = 0

Separate the equation into 2 possible cases

x = 0 x^{2} - 35 = 0

Solve the equation

More Steps

Evaluate

x^{2} - 35 = 0

Move the constant to the right-hand side and change its sign

x^{2} = 0 + 35

Removing 0 doesn't change the value,so remove it from the expression

x^{2} = 35

Take the root of both sides of the equation and remember to use both positive and negative roots

x = \pm 35

Separate the equation into 2 possible cases

x = 35 x = - 35

x = 0 x = 35 x = - 35

Solution

x_{1} = - 35, x_{2} = 0, x_{3} = 35

Alternative Form

x_{1} \approx - 5.91608, x_{2} = 0, x_{3} \approx 5.91608

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