Algebra
Calculus
Trigonometry
Matrix
Question
Solve the equation
x1=−3,x2=3,x3=5
Evaluate
(x2−9)×2(x2−2x−15)×2=0
Multiply the terms
More Steps
Evaluate
(x2−9)×2(x2−2x−15)×2
Multiply the terms
(x2−9)×4(x2−2x−15)
Multiply the first two terms
4(x2−9)(x2−2x−15)
4(x2−9)(x2−2x−15)=0
Elimination the left coefficient
(x2−9)(x2−2x−15)=0
Separate the equation into 2 possible cases
x2−9=0x2−2x−15=0
Solve the equation
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Evaluate
x2−9=0
Move the constant to the right-hand side and change its sign
x2=0+9
Removing 0 doesn't change the value,so remove it from the expression
x2=9
Take the root of both sides of the equation and remember to use both positive and negative roots
x=±9
Simplify the expression
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Evaluate
9
Write the number in exponential form with the base of 3
32
Reduce the index of the radical and exponent with 2
3
x=±3
Separate the equation into 2 possible cases
x=3x=−3
x=3x=−3x2−2x−15=0
Solve the equation
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Evaluate
x2−2x−15=0
Factor the expression
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Evaluate
x2−2x−15
Rewrite the expression
x2+(3−5)x−15
Calculate
x2+3x−5x−15
Rewrite the expression
x×x+x×3−5x−5×3
Factor out x from the expression
x(x+3)−5x−5×3
Factor out −5 from the expression
x(x+3)−5(x+3)
Factor out x+3 from the expression
(x−5)(x+3)
(x−5)(x+3)=0
When the product of factors equals 0,at least one factor is 0
x−5=0x+3=0
Solve the equation for x
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Evaluate
x−5=0
Move the constant to the right-hand side and change its sign
x=0+5
Removing 0 doesn't change the value,so remove it from the expression
x=5
x=5x+3=0
Solve the equation for x
More Steps
Evaluate
x+3=0
Move the constant to the right-hand side and change its sign
x=0−3
Removing 0 doesn't change the value,so remove it from the expression
x=−3
x=5x=−3
x=3x=−3x=5x=−3
Find the union
x=3x=−3x=5
Solution
x1=−3,x2=3,x3=5
Show Solution
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