Solve (x^2+y^2-1)*x^2y^2=0

Question

Solve the equation

Solve for x

Solve for y

x = 0 x = - y^{2} + 1 x = - - y^{2} + 1

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Testing for symmetry about the origin

Testing for symmetry about the x-axis

Testing for symmetry about the y-axis

Symmetry with respect to the origin

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r = 0 r = 1 r = - 1

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Find the derivative with respect to x

Find the derivative with respect to y

\frac{d y}{d x} = \frac{- 2 y x ^{2} - y ^{3} + y}{2 x y ^{2} + x ^{3} - x}

Calculate

(x^{2} + y^{2} - 1) \cdot x^{2} y^{2} = 0

Simplify the expression

x^{2} (x^{2} + y^{2} - 1) y^{2} = 0

Take the derivative of both sides

\frac{d}{d x} (x^{2} (x^{2} + y^{2} - 1) y^{2}) = \frac{d}{d x} (0)

Calculate the derivative

More Steps

2 x^{3} y^{2} + 2 x y^{4} - 2 x y^{2} + 2 x^{3} y^{2} + 2 x^{2} y^{3} \frac{d y}{d x} + 2 x^{4} y \frac{d y}{d x} + 2 x^{2} y^{3} \frac{d y}{d x} - 2 x^{2} y \frac{d y}{d x} = \frac{d}{d x} (0)

Calculate the derivative

2 x^{3} y^{2} + 2 x y^{4} - 2 x y^{2} + 2 x^{3} y^{2} + 2 x^{2} y^{3} \frac{d y}{d x} + 2 x^{4} y \frac{d y}{d x} + 2 x^{2} y^{3} \frac{d y}{d x} - 2 x^{2} y \frac{d y}{d x} = 0

Calculate the sum or difference

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4 x^{3} y^{2} + 2 x y^{4} - 2 x y^{2} + (4 x^{2} y^{3} + 2 x^{4} y - 2 x^{2} y) \frac{d y}{d x} = 0

Move the constant to the right side

(4 x^{2} y^{3} + 2 x^{4} y - 2 x^{2} y) \frac{d y}{d x} = 0 - (4 x^{3} y^{2} + 2 x y^{4} - 2 x y^{2})

Subtract the terms

More Steps

(4 x^{2} y^{3} + 2 x^{4} y - 2 x^{2} y) \frac{d y}{d x} = - 4 x^{3} y^{2} - 2 x y^{4} + 2 x y^{2}

Divide both sides

\frac{( 4 x ^{2} y ^{3} + 2 x ^{4} y - 2 x ^{2} y ) \frac{d y}{d x}}{4 x ^{2} y ^{3} + 2 x ^{4} y - 2 x ^{2} y} = \frac{- 4 x ^{3} y ^{2} - 2 x y ^{4} + 2 x y ^{2}}{4 x ^{2} y ^{3} + 2 x ^{4} y - 2 x ^{2} y}

Divide the numbers

\frac{d y}{d x} = \frac{- 4 x ^{3} y ^{2} - 2 x y ^{4} + 2 x y ^{2}}{4 x ^{2} y ^{3} + 2 x ^{4} y - 2 x ^{2} y}

Solution

More Steps

\frac{d y}{d x} = \frac{- 2 y x ^{2} - y ^{3} + y}{2 x y ^{2} + x ^{3} - x}

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