Question
Simplify the expression
54x5−216x3
Evaluate
(x2−4)(x2×6x×9)
Remove the parentheses
(x2−4)x2×6x×9
Multiply the terms with the same base by adding their exponents
(x2−4)x2+1×6×9
Add the numbers
(x2−4)x3×6×9
Multiply the terms
(x2−4)x3×54
Use the commutative property to reorder the terms
(x2−4)×54x3
Multiply the terms
54x3(x2−4)
Apply the distributive property
54x3×x2−54x3×4
Multiply the terms
More Steps

Evaluate
x3×x2
Use the product rule an×am=an+m to simplify the expression
x3+2
Add the numbers
x5
54x5−54x3×4
Solution
54x5−216x3
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Factor the expression
54x3(x−2)(x+2)
Evaluate
(x2−4)(x2×6x×9)
Remove the parentheses
(x2−4)x2×6x×9
Multiply
More Steps

Multiply the terms
x2×6x×9
Multiply the terms with the same base by adding their exponents
x2+1×6×9
Add the numbers
x3×6×9
Multiply the terms
x3×54
Use the commutative property to reorder the terms
54x3
(x2−4)×54x3
Multiply the terms
54x3(x2−4)
Solution
54x3(x−2)(x+2)
Show Solution

Find the roots
x1=−2,x2=0,x3=2
Evaluate
(x2−4)(x2×6x×9)
To find the roots of the expression,set the expression equal to 0
(x2−4)(x2×6x×9)=0
Multiply
More Steps

Multiply the terms
x2×6x×9
Multiply the terms with the same base by adding their exponents
x2+1×6×9
Add the numbers
x3×6×9
Multiply the terms
x3×54
Use the commutative property to reorder the terms
54x3
(x2−4)×54x3=0
Multiply the terms
54x3(x2−4)=0
Elimination the left coefficient
x3(x2−4)=0
Separate the equation into 2 possible cases
x3=0x2−4=0
The only way a power can be 0 is when the base equals 0
x=0x2−4=0
Solve the equation
More Steps

Evaluate
x2−4=0
Move the constant to the right-hand side and change its sign
x2=0+4
Removing 0 doesn't change the value,so remove it from the expression
x2=4
Take the root of both sides of the equation and remember to use both positive and negative roots
x=±4
Simplify the expression
More Steps

Evaluate
4
Write the number in exponential form with the base of 2
22
Reduce the index of the radical and exponent with 2
2
x=±2
Separate the equation into 2 possible cases
x=2x=−2
x=0x=2x=−2
Solution
x1=−2,x2=0,x3=2
Show Solution
