Solve (x^3 x^2 x)(x-1)

Evaluate

(x^{3} \times x^{2} \times x) (x - 1)

To find the roots of the expression,set the expression equal to 0

(x^{3} \times x^{2} \times x) (x - 1) = 0

Multiply

More Steps

x^{6} (x - 1) = 0

Separate the equation into 2 possible cases

x^{6} = 0 x - 1 = 0

The only way a power can be 0 is when the base equals 0

x = 0 x - 1 = 0

Solve the equation

More Steps

x = 0 x = 1

Solution

x_{1} = 0, x_{2} = 1

Simplify the expression