Solve (x^3-16x^2 79x-120)^2

Question

Simplify the expression

126 3^{2} x^{6} + 303120 x^{3} + 14400

Show Solution

9 (421 x^{3} + 40)^{2}

Show Solution

x = - \frac{2 3 5 \times 42 1 ^{2}}{421}

Alternative Form

x \approx - 0.456309

Evaluate

(x^{3} - 16 x^{2} \times 79 x - 120)^{2}

To find the roots of the expression,set the expression equal to 0

(x^{3} - 16 x^{2} \times 79 x - 120)^{2} = 0

Multiply

More Steps

(x^{3} - 1264 x^{3} - 120)^{2} = 0

Subtract the terms

More Steps

(- 1263 x^{3} - 120)^{2} = 0

The only way a power can be 0 is when the base equals 0

- 1263 x^{3} - 120 = 0

Move the constant to the right-hand side and change its sign

- 1263 x^{3} = 0 + 120

Removing 0 doesn't change the value,so remove it from the expression

- 1263 x^{3} = 120

Change the signs on both sides of the equation

1263 x^{3} = - 120

Divide both sides

\frac{1263 x ^{3}}{1263} = \frac{- 120}{1263}

Divide the numbers

x^{3} = \frac{- 120}{1263}

Divide the numbers

More Steps

x^{3} = - \frac{40}{421}

Take the 3 -th root on both sides of the equation

3 x^{3} = 3 - \frac{40}{421}

Calculate

x = 3 - \frac{40}{421}

Solution

More Steps

x = - \frac{2 3 5 \times 42 1 ^{2}}{421}

Alternative Form

x \approx - 0.456309

Show Solution