Question
Simplify the expression
2x3−6x2+6x−2
Evaluate
(x−1)2×2(x−1)
Multiply the terms with the same base by adding their exponents
(x−1)2+1×2
Add the numbers
(x−1)3×2
Use the commutative property to reorder the terms
2(x−1)3
Expand the expression
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Evaluate
(x−1)3
Use (a−b)3=a3−3a2b+3ab2−b3 to expand the expression
x3−3x2×1+3x×12−13
Calculate
x3−3x2+3x−1
2(x3−3x2+3x−1)
Apply the distributive property
2x3−2×3x2+2×3x−2×1
Multiply the numbers
2x3−6x2+2×3x−2×1
Multiply the numbers
2x3−6x2+6x−2×1
Solution
2x3−6x2+6x−2
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Find the roots
x=1
Evaluate
(x−1)2×2(x−1)
To find the roots of the expression,set the expression equal to 0
(x−1)2×2(x−1)=0
Multiply
More Steps

Multiply the terms
(x−1)2×2(x−1)
Multiply the terms with the same base by adding their exponents
(x−1)2+1×2
Add the numbers
(x−1)3×2
Use the commutative property to reorder the terms
2(x−1)3
2(x−1)3=0
Rewrite the expression
(x−1)3=0
The only way a power can be 0 is when the base equals 0
x−1=0
Move the constant to the right-hand side and change its sign
x=0+1
Solution
x=1
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