Question Simplify the expression 2x5−15x4+90x3−270x2+405x−243−2x−3 Evaluate 2(x−3)5−(x−3)21Reduce fractions to a common denominator 2(x−3)5−2(x−3)21×2Write all numerators above the common denominator 2(x−3)5−(x−3)21×2Expand the expression 2x5−15x4+90x3−270x2+405x−243−(x−3)21×2Use the commutative property to reorder the terms 2x5−15x4+90x3−270x2+405x−243−2(x−3)21Solution 2x5−15x4+90x3−270x2+405x−243−2x−3 Show Solution