Question
Solve the inequality
Solve the inequality by testing the values in the interval
Solve the inequality by separating into cases
Solve for x
x∈(−∞,3)∪(4,+∞)
Evaluate
(x−3)(x−4)>0
Rewrite the expression
(x−3)(x−4)=0
Separate the equation into 2 possible cases
x−3=0x−4=0
Solve the equation
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Evaluate
x−3=0
Move the constant to the right-hand side and change its sign
x=0+3
Removing 0 doesn't change the value,so remove it from the expression
x=3
x=3x−4=0
Solve the equation
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Evaluate
x−4=0
Move the constant to the right-hand side and change its sign
x=0+4
Removing 0 doesn't change the value,so remove it from the expression
x=4
x=3x=4
Determine the test intervals using the critical values
x<33<x<4x>4
Choose a value form each interval
x1=2x2=27x3=5
To determine if x<3 is the solution to the inequality,test if the chosen value x=2 satisfies the initial inequality
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Evaluate
(2−3)(2−4)>0
Simplify
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Evaluate
(2−3)(2−4)
Subtract the numbers
(−1)(2−4)
Remove the parentheses
−(2−4)
Subtract the numbers
−(−2)
When there is - in front of an expression in parentheses change the sign of each term of the expression and remove the parentheses
2
2>0
Check the inequality
true
x<3 is the solutionx2=27x3=5
To determine if 3<x<4 is the solution to the inequality,test if the chosen value x=27 satisfies the initial inequality
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Evaluate
(27−3)(27−4)>0
Simplify
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Evaluate
(27−3)(27−4)
Subtract the numbers
21(27−4)
Subtract the numbers
21(−21)
Multiplying or dividing an odd number of negative terms equals a negative
−21×21
To multiply the fractions,multiply the numerators and denominators separately
−2×21
Multiply the numbers
−41
−41>0
Calculate
−0.25>0
Check the inequality
false
x<3 is the solution3<x<4 is not a solutionx3=5
To determine if x>4 is the solution to the inequality,test if the chosen value x=5 satisfies the initial inequality
More Steps

Evaluate
(5−3)(5−4)>0
Simplify
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Evaluate
(5−3)(5−4)
Subtract the numbers
2(5−4)
Subtract the numbers
2×1
Any expression multiplied by 1 remains the same
2
2>0
Check the inequality
true
x<3 is the solution3<x<4 is not a solutionx>4 is the solution
Solution
x∈(−∞,3)∪(4,+∞)
Show Solution
