Solve -10(s-3) 6s=58

Question

Solve the quadratic equation

Solve using the quadratic formula

Solve by completing the square

Solve using the PQ formula

s_{1} = \frac{45 - 1155}{30}, s_{2} = \frac{45 + 1155}{30}

Alternative Form

s_{1} \approx 0.367157, s_{2} \approx 2.632843

Evaluate

- 10 (s - 3) \times 6 s = 58

Multiply

More Steps

- 60 s (s - 3) = 58

Expand the expression

More Steps

- 60 s^{2} + 180 s = 58

Move the expression to the left side

- 60 s^{2} + 180 s - 58 = 0

Multiply both sides

60 s^{2} - 180 s + 58 = 0

Substitute a= 60,b= - 180 and c= 58 into the quadratic formula s = \frac{- b \pm b ^{2} - 4 a c}{2 a}

s = \frac{180 \pm ( - 180 ) ^{2} - 4 \times 60 \times 58}{2 \times 60}

Simplify the expression

s = \frac{180 \pm ( - 180 ) ^{2} - 4 \times 60 \times 58}{120}

Simplify the expression

More Steps

s = \frac{180 \pm 18480}{120}

Simplify the radical expression

More Steps

s = \frac{180 \pm 4 1155}{120}

Separate the equation into 2 possible cases

s = \frac{180 + 4 1155}{120} s = \frac{180 - 4 1155}{120}

Simplify the expression

More Steps

s = \frac{45 + 1155}{30} s = \frac{180 - 4 1155}{120}

Simplify the expression

More Steps

s = \frac{45 + 1155}{30} s = \frac{45 - 1155}{30}

Solution

s_{1} = \frac{45 - 1155}{30}, s_{2} = \frac{45 + 1155}{30}

Alternative Form

s_{1} \approx 0.367157, s_{2} \approx 2.632843

Show Solution