Solve -110v^3=-59v

Question

Solve the equation

v_{1} = - \frac{6490}{110}, v_{2} = 0, v_{3} = \frac{6490}{110}

Alternative Form

v_{1} \approx - 0.732369, v_{2} = 0, v_{3} \approx 0.732369

Evaluate

- 110 v^{3} = - 59 v

Add or subtract both sides

- 110 v^{3} - (- 59 v) = 0

If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses

- 110 v^{3} + 59 v = 0

Factor the expression

v (- 110 v^{2} + 59) = 0

Separate the equation into 2 possible cases

v = 0 - 110 v^{2} + 59 = 0

Solve the equation

More Steps

Evaluate

- 110 v^{2} + 59 = 0

Move the constant to the right-hand side and change its sign

- 110 v^{2} = 0 - 59

Removing 0 doesn't change the value,so remove it from the expression

- 110 v^{2} = - 59

Change the signs on both sides of the equation

110 v^{2} = 59

Divide both sides

\frac{110 v ^{2}}{110} = \frac{59}{110}

Divide the numbers

v^{2} = \frac{59}{110}

Take the root of both sides of the equation and remember to use both positive and negative roots

v = \pm \frac{59}{110}

Simplify the expression

More Steps

Evaluate

\frac{59}{110}

To take a root of a fraction,take the root of the numerator and denominator separately

\frac{59}{110}

Multiply by the Conjugate

\frac{59 \times 110}{110 \times 110}

Multiply the numbers

\frac{6490}{110 \times 110}

When a square root of an expression is multiplied by itself,the result is that expression

\frac{6490}{110}

v = \pm \frac{6490}{110}

Separate the equation into 2 possible cases

v = \frac{6490}{110} v = - \frac{6490}{110}

v = 0 v = \frac{6490}{110} v = - \frac{6490}{110}

Solution

v_{1} = - \frac{6490}{110}, v_{2} = 0, v_{3} = \frac{6490}{110}

Alternative Form

v_{1} \approx - 0.732369, v_{2} = 0, v_{3} \approx 0.732369

Show Solution

Solve the equation

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