Question
Solve the inequality
Solve the inequality by testing the values in the interval
Solve for x
x≥−32
Alternative Form
x∈[−32,+∞)
Evaluate
−2x3≤2−x3
Move the expression to the left side
−2x3−(2−x3)≤0
Subtract the terms
More Steps

Evaluate
−2x3−(2−x3)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
−2x3−2+x3
Add the terms
More Steps

Evaluate
−2x3+x3
Collect like terms by calculating the sum or difference of their coefficients
(−2+1)x3
Add the numbers
−x3
−x3−2
−x3−2≤0
Rewrite the expression
−x3−2=0
Move the constant to the right-hand side and change its sign
−x3=0+2
Removing 0 doesn't change the value,so remove it from the expression
−x3=2
Change the signs on both sides of the equation
x3=−2
Take the 3-th root on both sides of the equation
3x3=3−2
Calculate
x=3−2
An odd root of a negative radicand is always a negative
x=−32
Determine the test intervals using the critical values
x<−32x>−32
Choose a value form each interval
x1=−2x2=0
To determine if x<−32 is the solution to the inequality,test if the chosen value x=−2 satisfies the initial inequality
More Steps

Evaluate
−2(−2)3≤2−(−2)3
Multiply the terms
More Steps

Evaluate
−2(−2)3
Calculate the product
(−2)4
A negative base raised to an even power equals a positive
24
24≤2−(−2)3
Subtract the terms
More Steps

Simplify
2−(−2)3
Rewrite the expression
2−(−23)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
2+23
Evaluate the power
2+8
Add the numbers
10
24≤10
Calculate
16≤10
Check the inequality
false
x<−32 is not a solutionx2=0
To determine if x>−32 is the solution to the inequality,test if the chosen value x=0 satisfies the initial inequality
More Steps

Evaluate
−2×03≤2−03
Simplify
More Steps

Evaluate
−2×03
Calculate
−2×0
Any expression multiplied by 0 equals 0
0
0≤2−03
Simplify
More Steps

Evaluate
2−03
Calculate
2−0
Removing 0 doesn't change the value,so remove it from the expression
2
0≤2
Check the inequality
true
x<−32 is not a solutionx>−32 is the solution
The original inequality is a nonstrict inequality,so include the critical value in the solution
x≥−32 is the solution
Solution
x≥−32
Alternative Form
x∈[−32,+∞)
Show Solution
