Solve -2x^4-5x^3 3x^2

Question

Simplify the expression

- 2 x^{4} - 15 x^{5}

Evaluate

- 2 x^{4} - 5 x^{3} \times 3 x^{2}

Solution

More Steps

Evaluate

5 x^{3} \times 3 x^{2}

Multiply the terms

15 x^{3} \times x^{2}

Multiply the terms with the same base by adding their exponents

15 x^{3 + 2}

Add the numbers

15 x^{5}

- 2 x^{4} - 15 x^{5}

Show Solution

- x^{4} (2 + 15 x)

Evaluate

- 2 x^{4} - 5 x^{3} \times 3 x^{2}

Multiply

More Steps

Evaluate

5 x^{3} \times 3 x^{2}

Multiply the terms

15 x^{3} \times x^{2}

Multiply the terms with the same base by adding their exponents

15 x^{3 + 2}

Add the numbers

15 x^{5}

- 2 x^{4} - 15 x^{5}

Rewrite the expression

- x^{4} \times 2 - x^{4} \times 15 x

Solution

- x^{4} (2 + 15 x)

Show Solution

x_{1} = - \frac{2}{15}, x_{2} = 0

Alternative Form

x_{1} = - 0.1 \dot{3}, x_{2} = 0

Evaluate

- 2 x^{4} - 5 x^{3} \times 3 x^{2}

To find the roots of the expression,set the expression equal to 0

- 2 x^{4} - 5 x^{3} \times 3 x^{2} = 0

Multiply

More Steps

Multiply the terms

5 x^{3} \times 3 x^{2}

Multiply the terms

15 x^{3} \times x^{2}

Multiply the terms with the same base by adding their exponents

15 x^{3 + 2}

Add the numbers

15 x^{5}

- 2 x^{4} - 15 x^{5} = 0

Factor the expression

- x^{4} (2 + 15 x) = 0

Divide both sides

x^{4} (2 + 15 x) = 0

Separate the equation into 2 possible cases

x^{4} = 0 2 + 15 x = 0

The only way a power can be 0 is when the base equals 0

x = 0 2 + 15 x = 0

Solve the equation

More Steps

Evaluate

2 + 15 x = 0

Move the constant to the right-hand side and change its sign

15 x = 0 - 2

Removing 0 doesn't change the value,so remove it from the expression

15 x = - 2

Divide both sides

\frac{15 x}{15} = \frac{- 2}{15}

Divide the numbers

x = \frac{- 2}{15}

Use \frac{- a}{b} = \frac{a}{- b} = - \frac{a}{b} to rewrite the fraction

x = - \frac{2}{15}

x = 0 x = - \frac{2}{15}

Solution

x_{1} = - \frac{2}{15}, x_{2} = 0

Alternative Form

x_{1} = - 0.1 \dot{3}, x_{2} = 0

Show Solution