Question
Solve the equation
k1=−510,k2=0,k3=510
Alternative Form
k1≈−0.632456,k2=0,k3≈0.632456
Evaluate
−3×5k3=−6k
Multiply the numbers
−15k3=−6k
Add or subtract both sides
−15k3−(−6k)=0
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
−15k3+6k=0
Factor the expression
3k(−5k2+2)=0
Divide both sides
k(−5k2+2)=0
Separate the equation into 2 possible cases
k=0−5k2+2=0
Solve the equation
More Steps

Evaluate
−5k2+2=0
Move the constant to the right-hand side and change its sign
−5k2=0−2
Removing 0 doesn't change the value,so remove it from the expression
−5k2=−2
Change the signs on both sides of the equation
5k2=2
Divide both sides
55k2=52
Divide the numbers
k2=52
Take the root of both sides of the equation and remember to use both positive and negative roots
k=±52
Simplify the expression
More Steps

Evaluate
52
To take a root of a fraction,take the root of the numerator and denominator separately
52
Multiply by the Conjugate
5×52×5
Multiply the numbers
5×510
When a square root of an expression is multiplied by itself,the result is that expression
510
k=±510
Separate the equation into 2 possible cases
k=510k=−510
k=0k=510k=−510
Solution
k1=−510,k2=0,k3=510
Alternative Form
k1≈−0.632456,k2=0,k3≈0.632456
Show Solution
