Solve -4 x^2(5x^2 40)(x^3-27)(x \sqrt 5)=0

Evaluate

- 4 x^{2} (5 x^{2} \times 40) (x^{3} - 27) (x 5) = 0

Remove the parentheses

- 4 x^{2} \times 5 x^{2} \times 40 (x^{3} - 27) x 5 = 0

Multiply

More Steps

- 8005 \times x^{5} (x^{3} - 27) = 0

Change the sign

8005 \times x^{5} (x^{3} - 27) = 0

Elimination the left coefficient

x^{5} (x^{3} - 27) = 0

Separate the equation into 2 possible cases

x^{5} = 0 x^{3} - 27 = 0

The only way a power can be 0 is when the base equals 0

x = 0 x^{3} - 27 = 0

Solve the equation

More Steps

x = 0 x = 3

Solution

x_{1} = 0, x_{2} = 3

Solve the equation