Solve -5(2x-2) 5x 1=-14

Question

Solve the quadratic equation

Solve using the quadratic formula

Solve by completing the square

Solve using the PQ formula

x_{1} = \frac{5 - 53}{10}, x_{2} = \frac{5 + 53}{10}

Alternative Form

x_{1} \approx - 0.228011, x_{2} \approx 1.228011

Evaluate

- 5 (2 x - 2) \times 5 x \times 1 = - 14

Multiply the terms

More Steps

- 25 x (2 x - 2) = - 14

Expand the expression

More Steps

- 50 x^{2} + 50 x = - 14

Move the expression to the left side

- 50 x^{2} + 50 x + 14 = 0

Multiply both sides

50 x^{2} - 50 x - 14 = 0

Substitute a= 50,b= - 50 and c= - 14 into the quadratic formula x = \frac{- b \pm b ^{2} - 4 a c}{2 a}

x = \frac{50 \pm ( - 50 ) ^{2} - 4 \times 50 ( - 14 )}{2 \times 50}

Simplify the expression

x = \frac{50 \pm ( - 50 ) ^{2} - 4 \times 50 ( - 14 )}{100}

Simplify the expression

More Steps

x = \frac{50 \pm 5300}{100}

Simplify the radical expression

More Steps

x = \frac{50 \pm 10 53}{100}

Separate the equation into 2 possible cases

x = \frac{50 + 10 53}{100} x = \frac{50 - 10 53}{100}

Simplify the expression

More Steps

x = \frac{5 + 53}{10} x = \frac{50 - 10 53}{100}

Simplify the expression

More Steps

x = \frac{5 + 53}{10} x = \frac{5 - 53}{10}

Solution

x_{1} = \frac{5 - 53}{10}, x_{2} = \frac{5 + 53}{10}

Alternative Form

x_{1} \approx - 0.228011, x_{2} \approx 1.228011

Show Solution