Question
Solve the inequality
Solve the inequality by testing the values in the interval
Solve the inequality by separating into cases
n≥0
Alternative Form
n∈[0,+∞)
Evaluate
−5n2(−3n−1)≥n−95n
Subtract the terms
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Evaluate
n−95n
Collect like terms by calculating the sum or difference of their coefficients
(1−95)n
Subtract the numbers
−94n
−5n2(−3n−1)≥−94n
Move the expression to the left side
−5n2(−3n−1)−(−94n)≥0
Subtract the terms
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Evaluate
−5n2(−3n−1)−(−94n)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
−5n2(−3n−1)+94n
Expand the expression
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Calculate
−5n2(−3n−1)
Apply the distributive property
−5n2(−3n)−(−5n2×1)
Multiply the terms
15n3−(−5n2×1)
Any expression multiplied by 1 remains the same
15n3−(−5n2)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
15n3+5n2
15n3+5n2+94n
15n3+5n2+94n≥0
Rewrite the expression
15n3+5n2+94n=0
Factor the expression
n(15n2+5n+94)=0
Separate the equation into 2 possible cases
n=015n2+5n+94=0
Solve the equation
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Evaluate
15n2+5n+94=0
Add or subtract both sides
15n2+5n=−94
Divide both sides
1515n2+5n=15−94
Evaluate
n2+31n=−1594
Add the same value to both sides
n2+31n+361=−1594+361
Simplify the expression
(n+61)2=−1801123
Since the left-hand side is always positive or 0,and the right-hand side is always negative,the statement is false for any value of n
n∈/R
n=0n∈/R
Find the union
n=0
Determine the test intervals using the critical values
n<0n>0
Choose a value form each interval
n1=−1n2=1
To determine if n<0 is the solution to the inequality,test if the chosen value n=−1 satisfies the initial inequality
More Steps

Evaluate
−5(−1)2(−3(−1)−1)≥−94(−1)
Simplify
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Evaluate
−5(−1)2(−3(−1)−1)
Simplify
−5(−1)2(3−1)
Subtract the numbers
−5(−1)2×2
Evaluate the power
−5×1×2
Rewrite the expression
−5×2
Multiply the numbers
−10
−10≥−94(−1)
Simplify
−10≥94
Check the inequality
false
n<0 is not a solutionn2=1
To determine if n>0 is the solution to the inequality,test if the chosen value n=1 satisfies the initial inequality
More Steps

Evaluate
−5×12×(−3×1−1)≥−94×1
Simplify
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Evaluate
−5×12×(−3×1−1)
Any expression multiplied by 1 remains the same
−5×12×(−3−1)
Subtract the numbers
−5×12×(−4)
1 raised to any power equals to 1
−5×1×(−4)
Rewrite the expression
−5(−4)
Multiplying or dividing an even number of negative terms equals a positive
5×4
Multiply the numbers
20
20≥−94×1
Any expression multiplied by 1 remains the same
20≥−94
Check the inequality
true
n<0 is not a solutionn>0 is the solution
The original inequality is a nonstrict inequality,so include the critical value in the solution
n≥0 is the solution
Solution
n≥0
Alternative Form
n∈[0,+∞)
Show Solution
