Solve -y^28 y^2 = 2y^2y^2

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Type your math problem... -y^28 y^2 = 2y^2y^2

Question

Solve the equation

y = 0

Evaluate

- y^{2} \times 8 y^{2} = 2 y^{2} \times y^{2}

Multiply

More Steps

Evaluate

y^{2} \times 8 y^{2}

Multiply the terms with the same base by adding their exponents

y^{2 + 2} \times 8

Add the numbers

y^{4} \times 8

Use the commutative property to reorder the terms

8 y^{4}

- 8 y^{4} = 2 y^{2} \times y^{2}

Multiply

More Steps

Evaluate

2 y^{2} \times y^{2}

Multiply the terms with the same base by adding their exponents

2 y^{2 + 2}

Add the numbers

2 y^{4}

- 8 y^{4} = 2 y^{4}

Add or subtract both sides

- 8 y^{4} - 2 y^{4} = 0

Subtract the terms

More Steps

Evaluate

- 8 y^{4} - 2 y^{4}

Collect like terms by calculating the sum or difference of their coefficients

(- 8 - 2) y^{4}

Subtract the numbers

- 10 y^{4}

- 10 y^{4} = 0

Change the signs on both sides of the equation

10 y^{4} = 0

Rewrite the expression

y^{4} = 0

Solution

y = 0

Show Solution

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