Algebra
Calculus
Trigonometry
Matrix
Question
Simplify the expression
−3009−15s2
Evaluate
1−2400−610−s2×15
Use the commutative property to reorder the terms
1−2400−610−15s2
Solution
−3009−15s2
Show Solution
Factor the expression
−3(1003+5s2)
Evaluate
1−2400−610−s2×15
Use the commutative property to reorder the terms
1−2400−610−15s2
Subtract the numbers
−2399−610−15s2
Subtract the numbers
−3009−15s2
Solution
−3(1003+5s2)
Show Solution
Find the roots
s1=−55015i,s2=55015i
Alternative Form
s1≈−14.163333i,s2≈14.163333i
Evaluate
1−2400−610−s2×15
To find the roots of the expression,set the expression equal to 0
1−2400−610−s2×15=0
Subtract the numbers
−2399−610−s2×15=0
Use the commutative property to reorder the terms
−2399−610−15s2=0
Subtract the numbers
−3009−15s2=0
Move the constant to the right-hand side and change its sign
−15s2=0+3009
Removing 0 doesn't change the value,so remove it from the expression
−15s2=3009
Change the signs on both sides of the equation
15s2=−3009
Divide both sides
1515s2=15−3009
Divide the numbers
s2=15−3009
Divide the numbers
More Steps
Evaluate
15−3009
Cancel out the common factor 3
5−1003
Use b−a=−ba=−ba to rewrite the fraction
−51003
s2=−51003
Take the root of both sides of the equation and remember to use both positive and negative roots
s=±−51003
Simplify the expression
More Steps
Evaluate
−51003
Evaluate the power
51003×−1
Evaluate the power
51003×i
Evaluate the power
More Steps
Evaluate
51003
To take a root of a fraction,take the root of the numerator and denominator separately
51003
Multiply by the Conjugate
5×51003×5
Multiply the numbers
5×55015
When a square root of an expression is multiplied by itself,the result is that expression
55015
55015i
s=±55015i
Separate the equation into 2 possible cases
s=55015is=−55015i
Solution
s1=−55015i,s2=55015i
Alternative Form
s1≈−14.163333i,s2≈14.163333i
Show Solution