Question
Factor the expression
(1−h)(1+h+h2)(1+h3+h6)
Evaluate
1−h9
Rewrite the expression in exponential form
13−h9
Use a3−b3=(a−b)(a2+ab+b2) to factor the expression
(1−h3)(12+1×h3+h6)
1 raised to any power equals to 1
(1−h3)(1+1×h3+h6)
Any expression multiplied by 1 remains the same
(1−h3)(1+h3+h6)
Solution
More Steps

Evaluate
1−h3
Rewrite the expression in exponential form
13−h3
Use a3−b3=(a−b)(a2+ab+b2) to factor the expression
(1−h)(12+1×h+h2)
1 raised to any power equals to 1
(1−h)(1+1×h+h2)
Any expression multiplied by 1 remains the same
(1−h)(1+h+h2)
(1−h)(1+h+h2)(1+h3+h6)
Show Solution

Find the roots
h=1
Evaluate
1−h9
To find the roots of the expression,set the expression equal to 0
1−h9=0
Move the constant to the right-hand side and change its sign
−h9=0−1
Removing 0 doesn't change the value,so remove it from the expression
−h9=−1
Change the signs on both sides of the equation
h9=1
Take the 9-th root on both sides of the equation
9h9=91
Calculate
h=91
Solution
h=1
Show Solution
