Question Factor the expression (1−y)(1+y+y2) Evaluate 1−y3Rewrite the expression in exponential form 13−y3Use a3−b3=(a−b)(a2+ab+b2) to factor the expression (1−y)(12+1×y+y2)1 raised to any power equals to 1 (1−y)(1+1×y+y2)Solution (1−y)(1+y+y2) Show Solution Find the roots y=1 Evaluate 1−y3To find the roots of the expression,set the expression equal to 0 1−y3=0Move the constant to the right-hand side and change its sign −y3=0−1Removing 0 doesn't change the value,so remove it from the expression −y3=−1Change the signs on both sides of the equation y3=1Take the 3-th root on both sides of the equation 3y3=31Calculate y=31Solution y=1 Show Solution