Solve 10 - 6x - 9x^2 = -9x

Question

Solve the quadratic equation

Solve using the quadratic formula

Solve by completing the square

Solve using the PQ formula

x_{1} = \frac{1 - 41}{6}, x_{2} = \frac{1 + 41}{6}

Alternative Form

x_{1} \approx - 0.900521, x_{2} \approx 1.233854

Evaluate

10 - 6 x - 9 x^{2} = - 9 x

Move the expression to the left side

10 + 3 x - 9 x^{2} = 0

Rewrite in standard form

- 9 x^{2} + 3 x + 10 = 0

Multiply both sides

9 x^{2} - 3 x - 10 = 0

Substitute a= 9,b= - 3 and c= - 10 into the quadratic formula x = \frac{- b \pm b ^{2} - 4 a c}{2 a}

x = \frac{3 \pm ( - 3 ) ^{2} - 4 \times 9 ( - 10 )}{2 \times 9}

Simplify the expression

x = \frac{3 \pm ( - 3 ) ^{2} - 4 \times 9 ( - 10 )}{18}

Simplify the expression

More Steps

x = \frac{3 \pm 369}{18}

Simplify the radical expression

More Steps

x = \frac{3 \pm 3 41}{18}

Separate the equation into 2 possible cases

x = \frac{3 + 3 41}{18} x = \frac{3 - 3 41}{18}

Simplify the expression

More Steps

x = \frac{1 + 41}{6} x = \frac{3 - 3 41}{18}

Simplify the expression

More Steps

x = \frac{1 + 41}{6} x = \frac{1 - 41}{6}

Solution

x_{1} = \frac{1 - 41}{6}, x_{2} = \frac{1 + 41}{6}

Alternative Form

x_{1} \approx - 0.900521, x_{2} \approx 1.233854

Show Solution