Solve 10(2-b^2)=7(1 b^2)

Evaluate

10 (2 - b^{2}) = 7 (1 \times b^{2})

Remove the parentheses

10 (2 - b^{2}) = 7 \times 1 \times b^{2}

Multiply the terms

10 (2 - b^{2}) = 7 b^{2}

Expand the expression

More Steps

20 - 10 b^{2} = 7 b^{2}

Add or subtract both sides

- 17 b^{2} = - 20

Divide both sides

\frac{- 17 b ^{2}}{- 17} = \frac{- 20}{- 17}

Divide the numbers

b^{2} = \frac{20}{17}

Take the root of both sides of the equation and remember to use both positive and negative roots

b = \pm \frac{20}{17}

Simplify the expression

b = \pm \frac{2 85}{17}

Separate the equation into 2 possible cases

b = \frac{2 85}{17} b = - \frac{2 85}{17}

Solution

b_{1} = - \frac{2 85}{17}, b_{2} = \frac{2 85}{17}

Alternative Form

b_{1} \approx - 1.084652, b_{2} \approx 1.084652

Solve the quadratic equation