Solve 10a^2-26a-3=0

Question

Solve the quadratic equation

Solve using the quadratic formula

Solve by completing the square

Solve using the PQ formula

a_{1} = \frac{13 - 199}{10}, a_{2} = \frac{13 + 199}{10}

Alternative Form

a_{1} \approx - 0.110674, a_{2} \approx 2.710674

Evaluate

10 a^{2} - 26 a - 3 = 0

Substitute a= 10,b= - 26 and c= - 3 into the quadratic formula a = \frac{- b \pm b ^{2} - 4 a c}{2 a}

a = \frac{26 \pm ( - 26 ) ^{2} - 4 \times 10 ( - 3 )}{2 \times 10}

Simplify the expression

a = \frac{26 \pm ( - 26 ) ^{2} - 4 \times 10 ( - 3 )}{20}

Simplify the expression

More Steps

a = \frac{26 \pm 796}{20}

Simplify the radical expression

More Steps

a = \frac{26 \pm 2 199}{20}

Separate the equation into 2 possible cases

a = \frac{26 + 2 199}{20} a = \frac{26 - 2 199}{20}

Simplify the expression

More Steps

a = \frac{13 + 199}{10} a = \frac{26 - 2 199}{20}

Simplify the expression

More Steps

a = \frac{13 + 199}{10} a = \frac{13 - 199}{10}

Solution

a_{1} = \frac{13 - 199}{10}, a_{2} = \frac{13 + 199}{10}

Alternative Form

a_{1} \approx - 0.110674, a_{2} \approx 2.710674

Show Solution