Solve 10b^6-5 - ScanMath

Question

Factor the expression

5 (2 b^{6} - 1)

Evaluate

10 b^{6} - 5

Solution

5 (2 b^{6} - 1)

Show Solution

b_{1} = - \frac{6 32}{2}, b_{2} = \frac{6 32}{2}

Alternative Form

b_{1} \approx - 0.890899, b_{2} \approx 0.890899

Evaluate

10 b^{6} - 5

To find the roots of the expression,set the expression equal to 0

10 b^{6} - 5 = 0

Move the constant to the right-hand side and change its sign

10 b^{6} = 0 + 5

Removing 0 doesn't change the value,so remove it from the expression

10 b^{6} = 5

Divide both sides

\frac{10 b ^{6}}{10} = \frac{5}{10}

Divide the numbers

b^{6} = \frac{5}{10}

Cancel out the common factor 5

b^{6} = \frac{1}{2}

Take the root of both sides of the equation and remember to use both positive and negative roots

b = \pm 6 \frac{1}{2}

Simplify the expression

More Steps

Evaluate

6 \frac{1}{2}

To take a root of a fraction,take the root of the numerator and denominator separately

\frac{6 1}{6 2}

Simplify the radical expression

\frac{1}{6 2}

Multiply by the Conjugate

\frac{6 2 ^{5}}{6 2 \times 6 2 ^{5}}

Simplify

\frac{6 32}{6 2 \times 6 2 ^{5}}

Multiply the numbers

More Steps

Evaluate

62 \times 6 2^{5}

The product of roots with the same index is equal to the root of the product

6 2 \times 2^{5}

Calculate the product

6 2^{6}

Reduce the index of the radical and exponent with 6

2

\frac{6 32}{2}

b = \pm \frac{6 32}{2}

Separate the equation into 2 possible cases

b = \frac{6 32}{2} b = - \frac{6 32}{2}

Solution

b_{1} = - \frac{6 32}{2}, b_{2} = \frac{6 32}{2}

Alternative Form

b_{1} \approx - 0.890899, b_{2} \approx 0.890899

Show Solution