Solve 10t^2-5t-14

Evaluate

10 t^{2} - 5 t - 14

To find the roots of the expression,set the expression equal to 0

10 t^{2} - 5 t - 14 = 0

Substitute a= 10,b= - 5 and c= - 14 into the quadratic formula t = \frac{- b \pm b ^{2} - 4 a c}{2 a}

t = \frac{5 \pm ( - 5 ) ^{2} - 4 \times 10 ( - 14 )}{2 \times 10}

Simplify the expression

t = \frac{5 \pm ( - 5 ) ^{2} - 4 \times 10 ( - 14 )}{20}

Simplify the expression

More Steps

t = \frac{5 \pm 585}{20}

Simplify the radical expression

More Steps

t = \frac{5 \pm 3 65}{20}

Separate the equation into 2 possible cases

t = \frac{5 + 3 65}{20} t = \frac{5 - 3 65}{20}

Solution

t_{1} = \frac{5 - 3 65}{20}, t_{2} = \frac{5 + 3 65}{20}

Alternative Form

t_{1} \approx - 0.959339, t_{2} \approx 1.459339

Find the roots