Solve 110(1 + x)^2 - 221(1 + x) + 110 = 0

Question

Solve the quadratic equation

Solve by factoring

Solve using the quadratic formula

Solve by completing the square

x_{1} = - \frac{1}{11}, x_{2} = \frac{1}{10}

Alternative Form

x_{1} = - 0. \dot{0} \dot{9}, x_{2} = 0.1

Evaluate

110 (1 + x)^{2} - 221 (1 + x) + 110 = 0

Expand the expression

More Steps

- 1 - x + 110 x^{2} = 0

Factor the expression

More Steps

(- 1 + 10 x) (1 + 11 x) = 0

When the product of factors equals 0,at least one factor is 0

- 1 + 10 x = 0 1 + 11 x = 0

Solve the equation for x

More Steps

x = \frac{1}{10} 1 + 11 x = 0

Solve the equation for x

More Steps

x = \frac{1}{10} x = - \frac{1}{11}

Solution

x_{1} = - \frac{1}{11}, x_{2} = \frac{1}{10}

Alternative Form

x_{1} = - 0. \dot{0} \dot{9}, x_{2} = 0.1

Show Solution