Solve 12h - 7h^36

Question

Simplify the expression

12 h - 42 h^{3}

Evaluate

12 h - 7 h^{3} \times 6

Solution

12 h - 42 h^{3}

Show Solution

6 h (2 - 7 h^{2})

Evaluate

12 h - 7 h^{3} \times 6

Multiply the terms

12 h - 42 h^{3}

Rewrite the expression

6 h \times 2 - 6 h \times 7 h^{2}

Solution

6 h (2 - 7 h^{2})

Show Solution

h_{1} = - \frac{14}{7}, h_{2} = 0, h_{3} = \frac{14}{7}

Alternative Form

h_{1} \approx - 0.534522, h_{2} = 0, h_{3} \approx 0.534522

Evaluate

12 h - 7 h^{3} \times 6

To find the roots of the expression,set the expression equal to 0

12 h - 7 h^{3} \times 6 = 0

Multiply the terms

12 h - 42 h^{3} = 0

Factor the expression

6 h (2 - 7 h^{2}) = 0

Divide both sides

h (2 - 7 h^{2}) = 0

Separate the equation into 2 possible cases

h = 0 2 - 7 h^{2} = 0

Solve the equation

More Steps

Evaluate

2 - 7 h^{2} = 0

Move the constant to the right-hand side and change its sign

- 7 h^{2} = 0 - 2

Removing 0 doesn't change the value,so remove it from the expression

- 7 h^{2} = - 2

Change the signs on both sides of the equation

7 h^{2} = 2

Divide both sides

\frac{7 h ^{2}}{7} = \frac{2}{7}

Divide the numbers

h^{2} = \frac{2}{7}

Take the root of both sides of the equation and remember to use both positive and negative roots

h = \pm \frac{2}{7}

Simplify the expression

More Steps

Evaluate

\frac{2}{7}

To take a root of a fraction,take the root of the numerator and denominator separately

\frac{2}{7}

Multiply by the Conjugate

\frac{2 \times 7}{7 \times 7}

Multiply the numbers

\frac{14}{7 \times 7}

When a square root of an expression is multiplied by itself,the result is that expression

\frac{14}{7}

h = \pm \frac{14}{7}

Separate the equation into 2 possible cases

h = \frac{14}{7} h = - \frac{14}{7}

h = 0 h = \frac{14}{7} h = - \frac{14}{7}

Solution

h_{1} = - \frac{14}{7}, h_{2} = 0, h_{3} = \frac{14}{7}

Alternative Form

h_{1} \approx - 0.534522, h_{2} = 0, h_{3} \approx 0.534522

Show Solution