Solve 12n^(2)-44n-40

Question

Factor the expression

4 (3 n^{2} - 11 n - 10)

Show Solution

n_{1} = \frac{11 - 241}{6}, n_{2} = \frac{11 + 241}{6}

Alternative Form

n_{1} \approx - 0.754029, n_{2} \approx 4.420696

Evaluate

12 n^{2} - 44 n - 40

To find the roots of the expression,set the expression equal to 0

12 n^{2} - 44 n - 40 = 0

Substitute a= 12,b= - 44 and c= - 40 into the quadratic formula n = \frac{- b \pm b ^{2} - 4 a c}{2 a}

n = \frac{44 \pm ( - 44 ) ^{2} - 4 \times 12 ( - 40 )}{2 \times 12}

Simplify the expression

n = \frac{44 \pm ( - 44 ) ^{2} - 4 \times 12 ( - 40 )}{24}

Simplify the expression

More Steps

n = \frac{44 \pm 3856}{24}

Simplify the radical expression

More Steps

n = \frac{44 \pm 4 241}{24}

Separate the equation into 2 possible cases

n = \frac{44 + 4 241}{24} n = \frac{44 - 4 241}{24}

Simplify the expression

More Steps

n = \frac{11 + 241}{6} n = \frac{44 - 4 241}{24}

Simplify the expression

More Steps

n = \frac{11 + 241}{6} n = \frac{11 - 241}{6}

Solution

n_{1} = \frac{11 - 241}{6}, n_{2} = \frac{11 + 241}{6}

Alternative Form

n_{1} \approx - 0.754029, n_{2} \approx 4.420696

Show Solution