Question
Simplify the expression
32v2−240
Evaluate
(12×18v)v−80
Remove the parentheses
12×18vv−80
Multiply the terms
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Multiply the terms
12×18vv
Multiply the terms
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Multiply the terms
12×18v
Cancel out the common factor 6
2×3v
Multiply the terms
32v
32vv
Multiply the terms
32v×v
Multiply the terms
32v2
32v2−80
Reduce fractions to a common denominator
32v2−380×3
Write all numerators above the common denominator
32v2−80×3
Solution
32v2−240
Show Solution

Find the roots
v1=−230,v2=230
Alternative Form
v1≈−10.954451,v2≈10.954451
Evaluate
(12×18v)v−80
To find the roots of the expression,set the expression equal to 0
(12×18v)v−80=0
Multiply the terms
More Steps

Multiply the terms
12×18v
Cancel out the common factor 6
2×3v
Multiply the terms
32v
32vv−80=0
Multiply the terms
More Steps

Multiply the terms
32vv
Multiply the terms
32v×v
Multiply the terms
32v2
32v2−80=0
Subtract the terms
More Steps

Simplify
32v2−80
Reduce fractions to a common denominator
32v2−380×3
Write all numerators above the common denominator
32v2−80×3
Multiply the numbers
32v2−240
32v2−240=0
Simplify
2v2−240=0
Move the constant to the right side
2v2=240
Divide both sides
22v2=2240
Divide the numbers
v2=2240
Divide the numbers
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Evaluate
2240
Reduce the numbers
1120
Calculate
120
v2=120
Take the root of both sides of the equation and remember to use both positive and negative roots
v=±120
Simplify the expression
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Evaluate
120
Write the expression as a product where the root of one of the factors can be evaluated
4×30
Write the number in exponential form with the base of 2
22×30
The root of a product is equal to the product of the roots of each factor
22×30
Reduce the index of the radical and exponent with 2
230
v=±230
Separate the equation into 2 possible cases
v=230v=−230
Solution
v1=−230,v2=230
Alternative Form
v1≈−10.954451,v2≈10.954451
Show Solution
