Question
12y2−4y−5
Factor the expression
(2y+1)(6y−5)
Evaluate
12y2−4y−5
Rewrite the expression
12y2+(−10+6)y−5
Calculate
12y2−10y+6y−5
Rewrite the expression
2y×6y−2y×5+6y−5
Factor out 2y from the expression
2y(6y−5)+6y−5
Solution
(2y+1)(6y−5)
Show Solution

Find the roots
y1=−21,y2=65
Alternative Form
y1=−0.5,y2=0.83˙
Evaluate
12y2−4y−5
To find the roots of the expression,set the expression equal to 0
12y2−4y−5=0
Factor the expression
More Steps

Evaluate
12y2−4y−5
Rewrite the expression
12y2+(−10+6)y−5
Calculate
12y2−10y+6y−5
Rewrite the expression
2y×6y−2y×5+6y−5
Factor out 2y from the expression
2y(6y−5)+6y−5
Factor out 6y−5 from the expression
(2y+1)(6y−5)
(2y+1)(6y−5)=0
When the product of factors equals 0,at least one factor is 0
2y+1=06y−5=0
Solve the equation for y
More Steps

Evaluate
2y+1=0
Move the constant to the right-hand side and change its sign
2y=0−1
Removing 0 doesn't change the value,so remove it from the expression
2y=−1
Divide both sides
22y=2−1
Divide the numbers
y=2−1
Use b−a=−ba=−ba to rewrite the fraction
y=−21
y=−216y−5=0
Solve the equation for y
More Steps

Evaluate
6y−5=0
Move the constant to the right-hand side and change its sign
6y=0+5
Removing 0 doesn't change the value,so remove it from the expression
6y=5
Divide both sides
66y=65
Divide the numbers
y=65
y=−21y=65
Solution
y1=−21,y2=65
Alternative Form
y1=−0.5,y2=0.83˙
Show Solution
