Algebra
Calculus
Trigonometry
Matrix
Question
Solve the equation
k=14
Evaluate
13=2(k−6)−3
Swap the sides of the equation
2(k−6)−3=13
Move the expression to the left side
2(k−6)−3−13=0
Subtract the numbers
2(k−6)−16=0
Calculate
More Steps
Evaluate
2(k−6)−16
Expand the expression
More Steps
Calculate
2(k−6)
Apply the distributive property
2k−2×6
Multiply the numbers
2k−12
2k−12−16
Subtract the numbers
2k−28
2k−28=0
Move the constant to the right-hand side and change its sign
2k=0+28
Removing 0 doesn't change the value,so remove it from the expression
2k=28
Divide both sides
22k=228
Divide the numbers
k=228
Solution
More Steps
Evaluate
228
Reduce the numbers
114
Calculate
14
k=14
Show Solution
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