Question Solve the equation(The real numbers system) k1≈−0.304935,k2≈1.133885 Evaluate 14k3×k−16k=5Evaluate More Steps Evaluate 14k3×kMultiply the terms with the same base by adding their exponents 14k3+1Add the numbers 14k4 14k4−16k=5Move the expression to the left side 14k4−16k−5=0Solution k1≈−0.304935,k2≈1.133885 Show Solution Solve the equation(The complex numbers system) k1≈−0.414475−0.927971i,k2≈−0.304935,k3≈−0.414475+0.927971i,k4≈1.133885 Evaluate 14k3×k−16k=5Multiply More Steps Evaluate 14k3×kMultiply the terms with the same base by adding their exponents 14k3+1Add the numbers 14k4 14k4−16k=5Move the expression to the left side 14k4−16k−5=0Calculate k≈1.133885k≈−0.414475+0.927971ik≈−0.304935k≈−0.414475−0.927971iSolution k1≈−0.414475−0.927971i,k2≈−0.304935,k3≈−0.414475+0.927971i,k4≈1.133885 Show Solution Graph