Question
Solve the quadratic equation
Solve using the quadratic formula
Solve by completing the square
Solve using the PQ formula
x1=52−36,x2=52+36
Alternative Form
x1≈−1.069694,x2≈1.869694
Evaluate
15x2−30=12x
Move the expression to the left side
15x2−30−12x=0
Rewrite in standard form
15x2−12x−30=0
Substitute a=15,b=−12 and c=−30 into the quadratic formula x=2a−b±b2−4ac
x=2×1512±(−12)2−4×15(−30)
Simplify the expression
x=3012±(−12)2−4×15(−30)
Simplify the expression
More Steps

Evaluate
(−12)2−4×15(−30)
Multiply
More Steps

Multiply the terms
4×15(−30)
Rewrite the expression
−4×15×30
Multiply the terms
−1800
(−12)2−(−1800)
Rewrite the expression
122−(−1800)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
122+1800
Evaluate the power
144+1800
Add the numbers
1944
x=3012±1944
Simplify the radical expression
More Steps

Evaluate
1944
Write the expression as a product where the root of one of the factors can be evaluated
324×6
Write the number in exponential form with the base of 18
182×6
The root of a product is equal to the product of the roots of each factor
182×6
Reduce the index of the radical and exponent with 2
186
x=3012±186
Separate the equation into 2 possible cases
x=3012+186x=3012−186
Simplify the expression
More Steps

Evaluate
x=3012+186
Divide the terms
More Steps

Evaluate
3012+186
Rewrite the expression
306(2+36)
Cancel out the common factor 6
52+36
x=52+36
x=52+36x=3012−186
Simplify the expression
More Steps

Evaluate
x=3012−186
Divide the terms
More Steps

Evaluate
3012−186
Rewrite the expression
306(2−36)
Cancel out the common factor 6
52−36
x=52−36
x=52+36x=52−36
Solution
x1=52−36,x2=52+36
Alternative Form
x1≈−1.069694,x2≈1.869694
Show Solution
