Question
Solve the inequality
Solve the inequality by testing the values in the interval
Solve the inequality by separating into cases
x≤0
Alternative Form
x∈(−∞,0]
Evaluate
15x−3x×1−5x×115−x2×2x≥0
Simplify
More Steps

Evaluate
15x−3x×1−5x×115−x2×2x
Multiply the terms
15x−3x−5x×115−x2×2x
Multiply the terms
15x−3x−575x−x2×2x
Multiply
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Multiply the terms
−x2×2x
Multiply the terms with the same base by adding their exponents
−x2+1×2
Add the numbers
−x3×2
Use the commutative property to reorder the terms
−2x3
15x−3x−575x−2x3
Subtract the terms
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Evaluate
15x−3x−575x
Collect like terms by calculating the sum or difference of their coefficients
(15−3−575)x
Subtract the numbers
−563x
−563x−2x3
−563x−2x3≥0
Rewrite the expression
−563x−2x3=0
Factor the expression
−x(563+2x2)=0
Divide both sides
x(563+2x2)=0
Separate the equation into 2 possible cases
x=0563+2x2=0
Solve the equation
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Evaluate
563+2x2=0
Move the constant to the right-hand side and change its sign
2x2=0−563
Removing 0 doesn't change the value,so remove it from the expression
2x2=−563
Divide both sides
22x2=2−563
Divide the numbers
x2=2−563
Use b−a=−ba=−ba to rewrite the fraction
x2=−2563
Calculate
x∈/R
x=0x∈/R
Find the union
x=0
Determine the test intervals using the critical values
x<0x>0
Choose a value form each interval
x1=−1x2=1
To determine if x<0 is the solution to the inequality,test if the chosen value x=−1 satisfies the initial inequality
More Steps

Evaluate
−563(−1)−2(−1)3≥0
Simplify
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Evaluate
−563(−1)−2(−1)3
Simplify
563−2(−1)3
Multiply the terms
563−(−2)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
563+2
Add the numbers
565
565≥0
Check the inequality
true
x<0 is the solutionx2=1
To determine if x>0 is the solution to the inequality,test if the chosen value x=1 satisfies the initial inequality
More Steps

Evaluate
−563×1−2×13≥0
Simplify
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Evaluate
−563×1−2×13
1 raised to any power equals to 1
−563×1−2×1
Any expression multiplied by 1 remains the same
−563−2×1
Any expression multiplied by 1 remains the same
−563−2
Subtract the numbers
−565
−565≥0
Check the inequality
false
x<0 is the solutionx>0 is not a solution
The original inequality is a nonstrict inequality,so include the critical value in the solution
x≤0 is the solution
Solution
x≤0
Alternative Form
x∈(−∞,0]
Show Solution
