Solve 16^(3x-4)=64^(x 1)

Evaluate

1 6^{3 x - 4} = 6 4^{x \times 1}

Any expression multiplied by 1 remains the same

1 6^{3 x - 4} = 6 4^{x}

Rewrite the expression

More Steps

4^{6 x - 8} = 6 4^{x}

Rewrite the expression

More Steps

4^{6 x - 8} = 4^{3 x}

Since the bases are the same,set the exponents equal

6 x - 8 = 3 x

Move the variable to the left side

6 x - 8 - 3 x = 0

Subtract the terms

More Steps

3 x - 8 = 0

Move the constant to the right side

3 x = 0 + 8

Removing 0 doesn't change the value,so remove it from the expression

3 x = 8

Divide both sides

\frac{3 x}{3} = \frac{8}{3}

Solution

x = \frac{8}{3}

Alternative Form

x = 2. \dot{6}

Solve the equation