Question
Factor the expression
4(2n−1)(2n+1)
Evaluate
16n2−4
Factor out 4 from the expression
4(4n2−1)
Solution
More Steps

Evaluate
4n2−1
Rewrite the expression in exponential form
(2n)2−12
Use a2−b2=(a−b)(a+b) to factor the expression
(2n−1)(2n+1)
4(2n−1)(2n+1)
Show Solution

Find the roots
n1=−21,n2=21
Alternative Form
n1=−0.5,n2=0.5
Evaluate
16n2−4
To find the roots of the expression,set the expression equal to 0
16n2−4=0
Move the constant to the right-hand side and change its sign
16n2=0+4
Removing 0 doesn't change the value,so remove it from the expression
16n2=4
Divide both sides
1616n2=164
Divide the numbers
n2=164
Cancel out the common factor 4
n2=41
Take the root of both sides of the equation and remember to use both positive and negative roots
n=±41
Simplify the expression
More Steps

Evaluate
41
To take a root of a fraction,take the root of the numerator and denominator separately
41
Simplify the radical expression
41
Simplify the radical expression
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Evaluate
4
Write the number in exponential form with the base of 2
22
Reduce the index of the radical and exponent with 2
2
21
n=±21
Separate the equation into 2 possible cases
n=21n=−21
Solution
n1=−21,n2=21
Alternative Form
n1=−0.5,n2=0.5
Show Solution
