Solve 16x^2 8x-1 - ScanMath

Question

Simplify the expression

128 x^{3} - 1

Evaluate

16 x^{2} \times 8 x - 1

Solution

More Steps

Evaluate

16 x^{2} \times 8 x

Multiply the terms

128 x^{2} \times x

Multiply the terms with the same base by adding their exponents

128 x^{2 + 1}

Add the numbers

128 x^{3}

128 x^{3} - 1

Show Solution

x = \frac{3 4}{8}

Alternative Form

x \approx 0.198425

Evaluate

16 x^{2} \times 8 x - 1

To find the roots of the expression,set the expression equal to 0

16 x^{2} \times 8 x - 1 = 0

Multiply

More Steps

Multiply the terms

16 x^{2} \times 8 x

Multiply the terms

128 x^{2} \times x

Multiply the terms with the same base by adding their exponents

128 x^{2 + 1}

Add the numbers

128 x^{3}

128 x^{3} - 1 = 0

Move the constant to the right-hand side and change its sign

128 x^{3} = 0 + 1

Removing 0 doesn't change the value,so remove it from the expression

128 x^{3} = 1

Divide both sides

\frac{128 x ^{3}}{128} = \frac{1}{128}

Divide the numbers

x^{3} = \frac{1}{128}

Take the 3 -th root on both sides of the equation

3 x^{3} = 3 \frac{1}{128}

Calculate

x = 3 \frac{1}{128}

Solution

More Steps

Evaluate

3 \frac{1}{128}

To take a root of a fraction,take the root of the numerator and denominator separately

\frac{3 1}{3 128}

Simplify the radical expression

\frac{1}{3 128}

Simplify the radical expression

More Steps

Evaluate

3128

Write the expression as a product where the root of one of the factors can be evaluated

3 64 \times 2

Write the number in exponential form with the base of 4

3 4^{3} \times 2

The root of a product is equal to the product of the roots of each factor

3 4^{3} \times 32

Reduce the index of the radical and exponent with 3

432

\frac{1}{4 3 2}

Multiply by the Conjugate

\frac{3 2 ^{2}}{4 3 2 \times 3 2 ^{2}}

Simplify

\frac{3 4}{4 3 2 \times 3 2 ^{2}}

Multiply the numbers

More Steps

Evaluate

432 \times 3 2^{2}

Multiply the terms

4 \times 2

Multiply the terms

8

\frac{3 4}{8}

x = \frac{3 4}{8}

Alternative Form

x \approx 0.198425

Show Solution