Question
Solve the inequality
Solve the inequality by testing the values in the interval
Solve the inequality by separating into cases
x∈(−∞,1)∪(2,3)
Evaluate
2(x−1)(3−x)(x−2)×2>0
Multiply the terms
4(x−1)(3−x)(x−2)>0
Rewrite the expression
4(x−1)(3−x)(x−2)=0
Elimination the left coefficient
(x−1)(3−x)(x−2)=0
Separate the equation into 3 possible cases
x−1=03−x=0x−2=0
Solve the equation
More Steps

Evaluate
x−1=0
Move the constant to the right-hand side and change its sign
x=0+1
Removing 0 doesn't change the value,so remove it from the expression
x=1
x=13−x=0x−2=0
Solve the equation
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Evaluate
3−x=0
Move the constant to the right-hand side and change its sign
−x=0−3
Removing 0 doesn't change the value,so remove it from the expression
−x=−3
Change the signs on both sides of the equation
x=3
x=1x=3x−2=0
Solve the equation
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Evaluate
x−2=0
Move the constant to the right-hand side and change its sign
x=0+2
Removing 0 doesn't change the value,so remove it from the expression
x=2
x=1x=3x=2
Determine the test intervals using the critical values
x<11<x<22<x<3x>3
Choose a value form each interval
x1=0x2=23x3=25x4=4
To determine if x<1 is the solution to the inequality,test if the chosen value x=0 satisfies the initial inequality
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Evaluate
4(0−1)(3−0)(0−2)>0
Simplify
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Evaluate
4(0−1)(3−0)(0−2)
Removing 0 doesn't change the value,so remove it from the expression
4(−1)(3−0)(0−2)
Removing 0 doesn't change the value,so remove it from the expression
4(−1)×3(0−2)
Removing 0 doesn't change the value,so remove it from the expression
4(−1)×3(−2)
Any expression multiplied by 1 remains the same
4×3×2
Multiply the terms
12×2
Multiply the numbers
24
24>0
Check the inequality
true
x<1 is the solutionx2=23x3=25x4=4
To determine if 1<x<2 is the solution to the inequality,test if the chosen value x=23 satisfies the initial inequality
More Steps

Evaluate
4(23−1)(3−23)(23−2)>0
Simplify
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Evaluate
4(23−1)(3−23)(23−2)
Subtract the numbers
4×21(3−23)(23−2)
Subtract the numbers
4×21×23(23−2)
Subtract the numbers
4×21×23(−21)
Rewrite the expression
−4×21×23×21
Multiply the terms
−23
−23>0
Calculate
−1.5>0
Check the inequality
false
x<1 is the solution1<x<2 is not a solutionx3=25x4=4
To determine if 2<x<3 is the solution to the inequality,test if the chosen value x=25 satisfies the initial inequality
More Steps

Evaluate
4(25−1)(3−25)(25−2)>0
Simplify
More Steps

Evaluate
4(25−1)(3−25)(25−2)
Subtract the numbers
4×23(3−25)(25−2)
Subtract the numbers
4×23×21(25−2)
Subtract the numbers
4×23×21×21
Multiply the terms
6×21×21
Multiply the terms
3×21
Multiply the numbers
23
23>0
Calculate
1.5>0
Check the inequality
true
x<1 is the solution1<x<2 is not a solution2<x<3 is the solutionx4=4
To determine if x>3 is the solution to the inequality,test if the chosen value x=4 satisfies the initial inequality
More Steps

Evaluate
4(4−1)(3−4)(4−2)>0
Simplify
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Evaluate
4(4−1)(3−4)(4−2)
Subtract the numbers
4×3(3−4)(4−2)
Subtract the numbers
4×3(−1)(4−2)
Subtract the numbers
4×3(−1)×2
Any expression multiplied by 1 remains the same
−4×3×2
Multiply the terms
−24
−24>0
Check the inequality
false
x<1 is the solution1<x<2 is not a solution2<x<3 is the solutionx>3 is not a solution
Solution
x∈(−∞,1)∪(2,3)
Show Solution
